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InterviewSolution
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A wire of given length is doubled on itself and this process is repeated once again. By what factor does the resistance of the wire change? |
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Answer» Solution :As the length of the wire become `1/4`of the ORIGINAL length its area of cross-section become 4 times. So, NEW resistance `R.RHO (l.)/(A.) = rho ((1 //4))/(4A) = 1/(4 xx4) (rho 1/A) = R/16 ( :. R = rho l/A)` Thus, the new resistance is `1/16` of the original resistance. |
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