1.

A wire of given material having length l and area of cross-section A has a resistance of 4 n. What would be the resistance of another wire of the same material having length 1/2 and area of cross - section 2A ?

Answer»

SOLUTION :For FIRST wire :
`R_1= RHO l/A = 4Omega`
Now, for second wire :
`R_2=rho (1/2)/(2A) = (1/4) rho 1/4`
`R_2= 1/4 R_1( :. R_1 = rho 1/A)`
`:. R_2 = 1/4 xx 4 ( :. R_1 = 4Omega`given)
`:. R_2 = 1 Omega`
The resistance of the another wire is `1 Omega`.


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