1.

A wire of resistance R is stretched so that its length increases by 10%. The resistance of the wire increases by

Answer»

0.11
0.15
0.21
0.28

Solution :`LA =l_1 A_1`
` or A_1 = (l)/(l_1) a=(100)/(110) A`
but`R= RHO (l)/(A)`
`thereforeR_1rho(110)/(100)l xx (110)/(100A) =(121)/(100) ( rho (l)/(A))`
=21%( increase)


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