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A wire when bent in the form of a square encloses an area of 484 sq.cm. What will be the enclosed area when the same wire is bent into the form of a circle? (Take \(\pi= \frac{{22}}{7}\)) 1). 462 sq.cm2). 539 sq.cm3). 616 sq.cm4). 693 sq.cm |
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Answer» Area of a square = side × side Perimeter of a square = 4 × side Given, wire when bent in the form of a square encloses an area of 484 sq.CM Side = √484 = 22 cm Perimeter = 88 cm Same wire is USED to make a circle. Perimeter of a circle of RADIUS r = 2πr ⇒ 2πr = 88 ⇒ 44r/7 = 88 ⇒ r = 14 cm Area of a circle of radius r = πr2 Area enclosed by the circle $(= \frac{{22}}{7} \times {14^2})$ ⇒ Area enclosed by the circle = 616 sq. cm. |
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