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A wireof diameter 3mm is wounded around a cylinder whose height is 12 cm and radius 5 cm so as to cover the curved surfaceof the cylinder completely: find (i) length of the wire. (ii) mass of the wire assuming the density of copper to be 8.88 g per cm^(3) |
Answer» Diameter (width) of wire = 3m=0.3 cm So whole height of cylinder =0.3 n cm But whole height of cylinder =12 cm 0.3 `n=12 rarr n=(12)/(0.3)=(120)/(3)=40` So 40 revolutions are completed to wound the wire completely on the cylinder In Irevolution length of wire = 2 `PI`R In 40 revolutions length of wire =`40xx2pir` `=80xx(22)/(7)xx5cm=1257.14 cm` =12.57 m.(ii) Now RADIUS of wire`=(0.3)/(2)=0.15 cm` volume of wire =area of CROSS section`xx` length of wire `=pi(0.15)^(2)xx1257.14=88.898 cm^(3)` Mass of wire = volume `xx` density =88.898`xx`8.88 g=789.41 g Hence length of wire = 12.57 m and mass of wire =789.41 g ![]() |
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