1.

A wireof diameter 3mm is wounded around a cylinder whose height is 12 cm and radius 5 cm so as to cover the curved surfaceof the cylinder completely: find (i) length of the wire. (ii) mass of the wire assuming the density of copper to be 8.88 g per cm^(3)

Answer»


Solution :(i) Let the wire wounded around the cylinder completes n revolutions.
Diameter (width) of wire = 3m=0.3 cm
So whole height of cylinder =0.3 n cm
But whole height of cylinder =12 cm
0.3 `n=12 rarr n=(12)/(0.3)=(120)/(3)=40`
So 40 revolutions are completed to wound the wire completely on the cylinder
In Irevolution length of wire = 2 `PI`R
In 40 revolutions length of wire =`40xx2pir`
`=80xx(22)/(7)xx5cm=1257.14 cm`
=12.57 m.(ii) Now RADIUS of wire`=(0.3)/(2)=0.15 cm`
volume of wire =area of CROSS section`xx` length of wire
`=pi(0.15)^(2)xx1257.14=88.898 cm^(3)`
Mass of wire = volume `xx` density
=88.898`xx`8.88 g=789.41 g
Hence length of wire = 12.57 m
and mass of wire =789.41 g


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