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InterviewSolution
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A wooden artifact sample gave activity `32-beta` particles per second while the freshly cut wood gave activity of `64 beta` particles per second in Geiger Muller counter. Calculate the age of the wooden artifact `(t_(1//2) "of" C^(14) = 5760` years) |
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Answer» `(0.693)/(t_(1//2)) = (2.303)/(t_("age")) "log" ((N_(0))/(N))` `(0.693)/(5760) = (2.303)/(t_("age")) "log" ((64)/(32))` `t_("age") = 5760` years |
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