1.

(a) Write the mathematical expression for Joule's law of heating.(b) Compute the heat generated while transferring 96000 coulomb of charge in two hours through a potential difference of 40 V.

Answer»

SOLUTION :(a) As per mathematical expression for Joule.s law of heating
Heat produced H = VIt =`I^2Rt=(V^2)/(R)t`
When a voltage V is applied across a resistance R for time t so that a current I flows through it.
(B) Here charge Q = 96000 C, time t = 2 h and potential difference V = 40 V
`therefoe` Heat generated H=VIt = VQ
`implies`H = 40 x 96000 = 3840000 J = 3.84 x `10^6`J


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