1.

a) Write two points of difference between electric energy and electric power.b) An electric bulb of 200 Omegadraws a current of 1 ampere. Calculate the power of the bulb the potential different at its ends and the energy in KWh consumed burning it for 5h.

Answer»

Solution :a) Electric ENERGY: 1) The work done or energy supplied by the source in maintaining the flow of electric current is called electrical energy. It appeare in the form of heat given by
`VIt = (Vt)/(R) = VRt `
ii) It is EQUAL to the product of power and TIME
` E = P XX t`
iii) Its SI units is joule (J)
Electric power :
i) The time rate at which electric energy is consumed or disipated by an electrical device is called electric power and is given by
`P = vI = (v^2)/(R) = I^2 R`
ii)It is equal to rate of doing work by an energy source.
`P = w/t`
iii) Its SI unit is Watt (W)
1W = `1JS^(-1)`
(b)Power of the bulb
Power of the bulb,` P = I^2R = (1)^2 xx 200`
P= 200 W
Energy consumed by bulb in 5h in burning.
= Power x Time
= 200 x 5
= 1000 wh= 1Kwh.


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