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a) Write two points of difference between electric energy and electric power.b) An electric bulb of 200 Omegadraws a current of 1 ampere. Calculate the power of the bulb the potential different at its ends and the energy in KWh consumed burning it for 5h. |
Answer» Solution :a) Electric ENERGY: 1) The work done or energy supplied by the source in maintaining the flow of electric current is called electrical energy. It appeare in the form of heat given by `VIt = (Vt)/(R) = VRt ` ii) It is EQUAL to the product of power and TIME ` E = P XX t` iii) Its SI units is joule (J) Electric power : i) The time rate at which electric energy is consumed or disipated by an electrical device is called electric power and is given by `P = vI = (v^2)/(R) = I^2 R` ii)It is equal to rate of doing work by an energy source. `P = w/t` iii) Its SI unit is Watt (W) 1W = `1JS^(-1)` (b)Power of the bulb Power of the bulb,` P = I^2R = (1)^2 xx 200` P= 200 W Energy consumed by bulb in 5h in burning. = Power x Time = 200 x 5 = 1000 wh= 1Kwh. |
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