1.

ABC is a triangle inscribed in a circle, AC being the diameter of the circle. The length of AC is as much more than the length of BC as the length of BC is more than the length of AB. Find AC:AB.

Answer»

`5:3`
`5:4`
`6:5`
`3:2`

SOLUTION :`AC^(2)=AB^(2)+BC^(2)`. Consider AB as `x`, BC as `x +k` and AC as `x+2k`.


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