

InterviewSolution
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Add and express the sum as a mixed fraction:(i) \(\frac{-12}{5}\) and \(\frac{43}{10}\)(ii) \(\frac{-31}{6}\) and \(\frac{-27}{8}\) |
Answer» i) We add the given fraction \(\frac{12}{5}+\frac{43}{10}\) The L.C.M of 5 and 10 is 10 \(\frac{(-12\times2)}{(5\times2)}+\frac{(43\times1)}{(10\times1)}\\=\frac{-24}{10}+\frac{43}{10}\) The denominators are same we can add them directly.We get \(\frac{(-24+43)}{10}=\frac{19}{10}\) \(\therefore\) \(\frac{19}{10}\)can be written in mixed fraction as \(\frac{9}{10}{1}\) ii) We add the given fraction \(\frac{-31}{6}+\frac{-27}{8}\) The L.C.M of 6 and 8 is 24 \(\frac{(-31\times4)}{(6\times4)}+\frac{(-27\times3)}{(8\times3)}\\=\frac{-124}{24}+\frac{-81}{24}\) The denominators are same we can add them directly.We get \(\frac{(-124-81)}{24}=\frac{-205}{24}\) \(\frac{-205}{24}\) can be written in mixed fraction as \(-8\frac{13}{24}\) |
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