1.

Add and express the sum as a mixed fraction:(i) \(\frac{-12}{5}\) and \(\frac{43}{10}\)(ii) \(\frac{-31}{6}\) and \(\frac{-27}{8}\)

Answer»

i)  We add the given fraction

\(\frac{12}{5}+\frac{43}{10}\)

The L.C.M of 5 and 10  is 10

\(\frac{(-12\times2)}{(5\times2)}+\frac{(43\times1)}{(10\times1)}\\=\frac{-24}{10}+\frac{43}{10}\)

The denominators are same we can add them directly.We get

\(\frac{(-24+43)}{10}=\frac{19}{10}\)

\(\therefore\)  \(\frac{19}{10}\)can be written in mixed fraction as \(\frac{9}{10}{1}\)

ii)  We add the given fraction

\(\frac{-31}{6}+\frac{-27}{8}\)

The L.C.M of  6 and 8  is 24

\(\frac{(-31\times4)}{(6\times4)}+\frac{(-27\times3)}{(8\times3)}\\=\frac{-124}{24}+\frac{-81}{24}\)

The denominators are same we can add them directly.We get

\(\frac{(-124-81)}{24}=\frac{-205}{24}\)

\(\frac{-205}{24}\) can be written in mixed fraction as \(-8\frac{13}{24}\)



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