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Addition of `0.643`g of compound to `50`ml of benzene (density `=0.879mol^(-1)` ) lower the freezing point from`50.51^(@)C`. If `k_(f)` for benzene is `5.12` the molecule of the compound isA. `156.00`B. `312.00`C. `78.00`D. `468.000` |
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Answer» Correct Answer - A Weight of bezene =`Vxxd=50xx0.879g` `W=43.95g` Weight of compound =`0.643gm` `DeltaT_(f)=50.51-50.03=0.48` `:.DeltaT_(f)=K_(f)xx(w)/(m)xx(1000)/(w)` `0.48=5.12xx(0.643)/(m)xx(1000)/(43.95)` ` :.m=156.05` |
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