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Additive inverse of \(\frac{-5}{9}\) isA. \(\frac{-9}{5}\)B. 0C. \(\frac{5}{9}\) D. \(\frac{9}{5}\) |
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Answer» Additive inverse of a number \(\frac{a}{b}\) is the number \(-\frac{a}{b}\) such that, \(\frac{a}{b}+(\frac{-a}{b})=0\) Therefore, Additive inverse of \(\frac{-5}{9}\) is \(\frac{5}{9}\) C.) 5/9As the sum of additive inverse is always zero. Let the add. inv. be x. Then, -5/9 + x=0 x=5/9 Hope it helps. |
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