1.

After a certain lapse of time, fraction of radioactive polonium undecayed is found to be `12.5%` of the initial quantity. What is the duration of this time lapsed if the half life of polonium is 138 days ?A. `414` daysB. `407` daysC. `421` daysD. `410` days

Answer» Correct Answer - A
`(dN)/(dt)=lambda N`, here `N="avagadrono"//238, lambda=0.693//T_((1)/(2))`


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