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After emission of one `alpha` particle followed by one `beta`-particle from `""_(92)^(238)X`, the number of neutrons in the atom will beA. `140`B. `142`C. `144`D. `146` |
Answer» Correct Answer - B `._(92)U^(238)rarr._(92)x^(234)+._(2)He^(4)+._(-1)e^(0)` no of neutrons `=234 - 92 = 142` |
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