An air bubble of volume 1.0 cm^(3) rises from the bottom of a lake 40 m deep at a temperature of 12^(@) C. To what volume does it grow when it reaches the surface, which is at a temperature of 35^(@) C. ? Given 1 atm = 1.01 xx 10^(5) Pa.

An air bubble of volume 1.0 cm^(3) rises from the bottom of a lake 40

1.	An air bubble of volume 1.0 cm^(3) rises from the bottom of a lake 40 m deep at a temperature of 12^(@) C. To what volume does it grow when it reaches the surface, which is at a temperature of 35^(@) C. ? Given 1 atm = 1.01 xx 10^(5) Pa.
Answer» Solution :`V_(1)=10^(-6)m^(3)` Pressure on hubble `P_(1)=` WATER pressure `+` ATMOSPHERIC pressure `=pgh+Patm` `=4.93xx10^(5)PA` `T_(1)=285k`, `T_(2)=308k` `(P_(1)V_(1))/(T_(1))=(P_(2)V_(2))/(T_(2))` `V_(2)=(4.93xx10^(5)xx1xx10^(-6)xx308)/(285xx1.01xx10^(5))=5.3xx10^(-6)m^(3)`.