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An aircraft has weight of 300N at the time of landing. Calculate braking K.E. if stall speed is 10 m/s.(a) 1.529 KJ(b) 156 KJ(c) 23 KJ(d) 23.45 KJI got this question in an interview.Enquiry is from Landing Gear topic in chapter Landing Gear and Subsystems of Aircraft Design

Answer»

Correct option is (a) 1.529 KJ

Easiest explanation: GIVEN, Weight W = 300N, stall SPEED v = 10 m/s

Braking K.E. = 0.5*W*v^2 / g = 0.5*300*10^2 / 9.81 = 1.529 KJ.



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