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An `alpha` particle of momentum p is bombarded on the nucleus, the distance of the closest approach is r, if the momentum of `alpha`-particle is made to 6p, then the distance of the closest approach becomesA. `4r`B. `2r`C. `16r`D. `(r)/(36)` |
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Answer» Correct Answer - D `(p^(2))/(2m) =(q_(1)q_(2))/(r)` at closes approach |
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