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An aqueous solution freezes at 272.4 K while pure water freezes at 273 K. Given `K_(f)=1.86 K kg "mol"^(-1)`,`K_(b)=0.512 K kg "mol"^(-1)` and vapour pressure of water at 298 K = 23.756 mm Hg. Determine the following. Boiling point of the solution isA. `300.73 K`B. `373.165 K`C. `400 K`D. `273.15 K` |
Answer» Correct Answer - B Boiling point of solution `DeltaT_(f)=K_(b) xx m` `K_(b)=0.512 K kg mol^(-1)`,`m=0.322 m` ,`DeltaT_(b)=?` `DeltaT_(b)=0.512 xx 0.322 = 0.165^(@)` Boiling point of solution =`373 + 0.165 =373.165 K` |
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