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An aqueous solution of a non-volatile solute boils at `100.17^(@)C`. At what temperature will the solution freeze? (Given: `K_(b) = 0.512` and `K_(f) = 1.86`) |
Answer» We know that, `Delta T_(b) =` molality `xx K_(b)` 0.17 = molality `xx 0.512` Molality of the solution `=(0.17)/(0.512)m` Let depression in freezing point be `Delta T_(f)` `Delta T_(f)`= molality `xx K_(f)` `=(0.17)/(0.512)xx1.86 = 0.62^(@)C` Thus, the freezing point of the solution `= 0.00-0.62 = -0.62^(@)C`. |
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