1.

An electric heater having resistance equal to 5 is connected to electric source. If it produces 180 J of heat in one second, find the potential difference across the electric heater.

Answer»

SOLUTION :Given: RESISTANCE (R) = 5 `Omega`, Heat (H) produced per SECOND by heater= 180 J, time (t) = 1 s
To find:Potential difference (V)
Formula : `H=I^2Rt`
Solution : We know that, `H=I^2Rt =(V/R)^2 Rt =(V^2t)/R`
`THEREFORE V^2 ="HR"/t=(180xx5)/1 =900`
`V=sqrt900`=30
Potential difference is 30 V


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