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An electric heater of resistance 8 Omega draws 15 A from the service mains 2 hours. Calculate the rate at which heat is developed in the heater. |
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Answer» Solution :`R= 8 Omega I = 15 A t, = 2h =2 xx60 xx60 s ` `H= I^(2) Rt = (15)^(2) xx8xx2xx60xx60` Rate at which HEAT PRODUCED :` = (H)/(t)` `= (15^(2)xx8xx2xx60xx60)/(2xx60xx60)` = 1800 W |
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