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An electric iron of 1100 W is operated for 2 hours daily. What will be the electrical consumption expenses for that in the month of April? (The electric company charges Rs. 5 per unit of energy). |
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Answer» SOLUTION :Given : Power (P) = 1100 W, Time= 2 hrs Number of days in April = 30 Charges per unit (I kWh) = Rs. 5 To find : MONTHLY Expense Formula: ENERGY = Power x Time Solution : Energy consumed per day =1100 X 2 = 2200 Energy consumed for 30 days = 2200 x 30 = 66000 Wh `=66000/1000=`66 kWh Amount per unit = Rs. 5 Amount for 66 units = 66 x 5 = Rs. 330 [he electrical expenses for the month of April is Rs. 330. |
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