1.

An electric iron of 1100 W is operated for 2 hours daily. What will be the electrical consumption expenses for that in the month of April? (The electric company charges Rs. 5 per unit of energy).

Answer»

SOLUTION :Given : Power (P) = 1100 W, Time= 2 hrs
Number of days in April = 30
Charges per unit (I kWh) = Rs. 5
To find : MONTHLY Expense
Formula: ENERGY = Power x Time
Solution : Energy consumed per day =1100 X 2 = 2200
Energy consumed for 30 days = 2200 x 30 = 66000 Wh
`=66000/1000=`66 kWh
Amount per unit = Rs. 5
Amount for 66 units = 66 x 5 = Rs. 330
[he electrical expenses for the month of April is Rs. 330.


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