1.

An electric iron of 1100 W is operated for 2 hours daily. What will be the electrical consumption expenses for that in the month of April ? (The electric company charges Rs. 5 per unit of energy.)

Answer»


Solution :`"Given:Power (P)=1100 W = 1.1 kW,"`
Time (t) = 2 hour
To find:`""` Expense of using ELECTRIC iron in April month
`"Formulae:i.Energy"="Power"xx"time"`
`"II.Electrical consumption expenses "="Energy consumed "xx"charge per unit"`
`"Calculation:From FORMULA (i),"`
Energy consumed in one day
`=1.1xx2=2.2kWh`
`THEREFORE""` Energy consumed in the month of April (i.e. 30 days) will be,
`"Energy "=2.2xx30=66kWh="66 unit..."(because "1 kWh = 1 unit")`
From formula (ii),
Electrical consumption expenses
`=66xx5="Rs 330"`


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