An electric lamp of 24 Omega and a conductor of 6 Omega are connected in parallel to a 12 V battery. Calculate : (i) Total resistance (ii) Total current in the circuit Potential difference across the conductor.

An electric lamp of 24 Omega and a conductor of 6 Omega are connected

1.	An electric lamp of 24 Omega and a conductor of 6 Omega are connected in parallel to a 12 V battery. Calculate : (i) Total resistance (ii) Total current in the circuit Potential difference across the conductor.
Answer» Solution :`R_(1)= 24 OMEGA, R_(2) = 6 Omega, V=12 V` (i) `R = (R_(1)R_(2))/(R_(1)+R_(2))=(6xx24)/(30)=4.8 Omega` (ii) `I= (V)/(R)= (12V)/(4.8) =(10)/(4) A = 2.5A` (III) Potential difference across the conductor will be 12 V because these are joined acrolls the battery.