An electrical iron uses a power of 1100 W when set to higher temperature. If set to lower temperature, it uses 330 W power. Find out the electric current and the respective resistances for the two settings.The iron is connected to a potential difference of 220 V.

An electrical iron uses a power of 1100 W when set to higher temperatu

1.	An electrical iron uses a power of 1100 W when set to higher temperature. If set to lower temperature, it uses 330 W power. Find out the electric current and the respective resistances for the two settings.The iron is connected to a potential difference of 220 V.
Answer» Solution :`"GivenPotential difference (V) = 220 V."` Power used at HIGHER temperature `(P_(1))=1100W,` Power used at LOWER temperature `(P_(1))=1100W,` Power used at lower temperature `(P_(2))=330W`. `"To find:i.Electric current "(I_(1))" at higher temperature."` `"iiElectric current "(I_(2))" at lower temperature"` `"iii.Resistance "(R_(1))" at higher temperature"` `"iv.Resistance "(R_(2))" at lower temperature"` `"Formulae:i.P = VI.ii.V = 1 R"` CALCULATION : For higher temperature, From formula (i), `I_(1)=(P_(1))/(V)=(1100)/(220)=5A` From formula (ii), `R_(1)=(V)/(I_(1))=(220)/(5)=44Omega` For lower temperature, From formula (i), `I_(2)=(P_(2))/(V)=(330)/(220)=(3)/(2)=1.5A` From formula (ii), `R_(2)=(V)/(I_(2))=(220)/(1.5)=(220)/((3//2))` `=(220xx2)/(3)=(440)/(3)=146.67Omega`