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An Electromagnetic radiation of wavelength `242` nm is just sufficient to ionise a sodium atom .Calculate the ionisation energy of sodium in `KJ mol^(-1)`. |
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Answer» `lamda=242nm=242xx10^(-9)m` `c=3xx10^(8)ms^(-1)` `E=hv=h.(c)/(lamda)=6.6256xx10^(-34)xx(3xx10^(8))/(242xx10^(-9))` `=0.082xx10^(-17)J=0.082xx10^(-20)kJ` Energy per mole for ionisation `=0.082xx10^(-20)xx6.02xx10^(23)` `=493.6kJmol^(-1)`. |
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