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An electron, a proton and an alpha particle have kinetic energy of `16E,4E` and `E` respectively. What is the qualitavtive order of their de Broglie wavelengths :-A. `lambda_(e)gtlambda_(p)=lambda_(alpha)`B. `lambda_(p)=lambda_(alpha)gtlambda_(e)`C. `lambda_(p)gtlambda_(e)gtlambda_(alpha)`D. `lambda_(alpha)ltlambda_(e)gtgt lambda_(alpha)` |
Answer» Correct Answer - A `lambda_(e):lambda_(p):lambda_(alpha)=(1)/sqrt(m_(e)1.6E):(1)/(sqrtm_(p),4E):(1)/(sqrtm_(alpha.E))` Hence `lambda_(e):lambda_(p)=lambda_(alpha)` |
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