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An electron beam can undergo defraction by crystals .Through what potential should a beam of electrons beb acceleration so that its wavelength becomkes equal to `1.54 Å` |
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Answer» For an electron `(1)/(2) mv^(2) = eV` where v in the accelerating portential `lambda = (h)/("mu")` `:. (1)/(2)m((k)/(m lambda))^(2) = eV` `:. V = (1)/(2) xx (h^(2))/(m lambda^(2)e)`, subatituting all value , we get `= (1 xx (6.626 xx 10^(-34))^(2))/( 2 xx 9.108 xx 10^(-13) xx (1.54 xx 10^(-19))^(2) xx 1.602 xx 10^(-19))` |
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