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An electron beam can undergo defraction by crystals .Through what potential should a beam of electrons be accelerated so that its wavelength becomes equal to `1.54 Å`A. `54.3 volt`B. `63.3 volt`C. `66.2 volt`D. None of these |
Answer» Correct Answer - 2 For an electron `1/2 m u^(2)=eV` " " and `lambda=h/(m u)` Thus, `1/2 m=(h^(2))/(m^(2)lambda^(2))=eV` or `V=1/2h^(2)/(mlambda^(2)e)=(1xx(6.62xx10^(-34))^(2))/(2xx9.108xx10^(-31)(1.54xx10^(-10))^(2)xx1.602xx10^(-19))=63.3 volt.` |
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