1.

An electron in H-atom in its ground state absorbs ` 1.5` times as much energy as the minimum required for its escape ( i. e., 13 . 6 eV) from the atom . Calculate the wavelength of emitted electron.

Answer» ` E= hv + 1/2 m u^2`
` ( 13. 6 xx 3)/2 = 13. 6 + 1/2 m u^2`
` 1/2 m u^2 = 6.8 eV = 6. 8 xx 1. 602 xx 10^(-12) erg`
` :. U^2 = ( 6.8 xx 2 xx 1.602 xx 10^(-12))/( 9. 108 xx 10^(28))`
`therefore u = 1. 54 xx 10^8 cm //sec `.
` therefore lambda = h/( m u)= ( 6.626 xx 10^(27))/( 9. 108 xx 10^(-28) xx 1. 54 xx 10^8)`
` = 4 . 72 xx 10^(-8) xx 10 ^(-8) cm = 4. 72 Å`.


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