1.

An electron is moving with a kinetic energy of `4.55 xx 10^-25 J`. What will be Broglie wavelength for this electron ?A. `5.28 xx 10^-7 m`B. `7.28 xx 10^-7 m`C. `2 xx 10^-10 m`D. `3 xx 10^-5 m`

Answer» Correct Answer - B
(b) `KE = (1)/(2) mv^2 = 4.55 xx 10^-25`
`V^2 = (2 xx 4.55 xx 10^-25)/(9.1 xx 10^-31) = 1 xx 10^6`
`V = 10^3 m//s`
de Broglie wavelength `lamda = (h)/(mv)`
=`(6.626 xx 10^-34)/(9.1 xx 10^-31 xx 10^3) = 7.28 xx 10^-7 m`.


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