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An electron is moving with a kinetic energy of `4.55 xx 10^-25 J`. What will be Broglie wavelength for this electron ?A. `5.28 xx 10^-7 m`B. `7.28 xx 10^-7 m`C. `2 xx 10^-10 m`D. `3 xx 10^-5 m` |
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Answer» Correct Answer - B (b) `KE = (1)/(2) mv^2 = 4.55 xx 10^-25` `V^2 = (2 xx 4.55 xx 10^-25)/(9.1 xx 10^-31) = 1 xx 10^6` `V = 10^3 m//s` de Broglie wavelength `lamda = (h)/(mv)` =`(6.626 xx 10^-34)/(9.1 xx 10^-31 xx 10^3) = 7.28 xx 10^-7 m`. |
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