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An electron moving near an atomic nucleus has a speed of `6xx10^(6) +- 1% m//s`. What is the uncertainty in its position?

Answer» Correct Answer - `ge 1xx10^(-9) m`
Findding the uncertainty in speed `Deltau, Deltau =(6xx10^(6) m//s)(0.01)=6xx10^(4) m//s`
Calculating the uncertainty in position, `Deltax: Deltax ge (h)/(4pimDeltau) ge (6.626xx10^(-34) kg. m^(2)//s)/(4pi(9.11xx10^(-31) kg)(6xx10^(4) m//s)) ge 1xx10^(-9) m`


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