An element A burns with golden flame in air. It reacts with another element B, atomic number 17to give a product C. An aqueous solution of the product C on electrolysis gives a compound D and liberates hydrogen. Identify A, B, C and D. Also write down the equations for the reactions involved.

An element A burns with golden flame in air. It reacts with another el

1.	An element A burns with golden flame in air. It reacts with another element B, atomic number 17to give a product C. An aqueous solution of the product C on electrolysis gives a compound D and liberates hydrogen. Identify A, B, C and D. Also write down the equations for the reactions involved.
Answer» Solution : Since the element A burns with golden flame in AIR, it is sodium (Na) which has electronic configuration 2, 8, 1. The element B with atomic number 17 is CHLORINE which has electronic configuration 2, 8, 7. Na and Cl react to form NaCl which is an ionic compound. Aqueous solution of NaCl on electrolysis GIVES NAOH and Cl, gas. THUS D is NaOH. Reactions are given as under :