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An element is placed in 2nd group and 3rd period of the periodic table, burn in presence of oxygen to form a basic oxide : (i) Identify the element (ii) Write the electronic configuration (iii) Write the balanced equation when it burns in the presence of air. (iv) Write a balanced equation when this oxide is dissolved in water. (v) Draw the electron dot structure for the formation of this oxide. |
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Answer» Solution :(i) Magnesium. (II) Electronic configuration is 2,8, 2 (iii) `2Mg+O_(2)to2MgO` (iv) `MgO+H_(2)OtoMg(OH)_(2)` (V) `MG toMg^(2+)+2e^(-)` 2,8,22, 8 `O+2e^(-)toO^(-2)` 2,62,8 is electron dot STRUCTURE.
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