1.

An element is placed in 2nd group and 3rd period of the periodic table, burn in presence of oxygen to form a basic oxide : (i) Identify the element (ii) Write the electronic configuration (iii) Write the balanced equation when it burns in the presence of air. (iv) Write a balanced equation when this oxide is dissolved in water. (v) Draw the electron dot structure for the formation of this oxide.

Answer»

Solution :(i) Magnesium.
(II) Electronic configuration is 2,8, 2
(iii) `2Mg+O_(2)to2MgO`
(iv) `MgO+H_(2)OtoMg(OH)_(2)`
(V) `MG toMg^(2+)+2e^(-)`
2,8,22, 8
`O+2e^(-)toO^(-2)`
2,62,8
is electron dot STRUCTURE.


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