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An explosion of atomic bomb releases an energy of `7.6xx10^(13)J`. If `200 MeV` energy is released on fission of one `.^(235)U` atom calculate (i) the number of uranium atoms undergoing fission. (ii) the mass of uranium used in the atom bomb |
Answer» `E=7.6xx10^(13)J` , Energy released per fission`=200 MeV` `=200xx10^(6)xx1.6xx10^(-19)=3.2xx10^(-11)J` `"Number of uranium atoms"(n)=("Total energy")/("Energy per fission")` `n=(7.6xx10^(13))/(3.2xx10^(-11))=2.375xx10^(24)"atoms"` Avagadro number `(N)=6.023xx10^(23)"atoms"` Mass of uranium `=` `(nxx235)/(N)=(2.375xx10^(24)xx235)/(6.023xx10^(23))=92.66g` |
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