1.

An iceberg floats on fresh water with a part of it outside the water surface. Calculate the fraction of the volume of the iceberg which is below the water surface. Given : density of ice =917kgm^(-3), density of fresh water =1000kgm^(-3)

Answer»

Solution :By the PRINCIPLE of floatation
`("VOLUME of iceberg IMMERSED")/("Total volume of iceberg")=("Density of ice")/("Density of FRESH water")`
`917/1000=0.917`
Thus 0.917th part of volume of iceberg will reamin below the water SURFACE.


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