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An iceberg floats on fresh water with a part of it outside the water surface. Calculate the fraction of the volume of the iceberg which is below the water surface. Given : density of ice =917kgm^(-3), density of fresh water =1000kgm^(-3) |
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Answer» Solution :By the PRINCIPLE of floatation `("VOLUME of iceberg IMMERSED")/("Total volume of iceberg")=("Density of ice")/("Density of FRESH water")` `917/1000=0.917` Thus 0.917th part of volume of iceberg will reamin below the water SURFACE. |
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