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An ideal transformer is rated as 2400/120 V, 9.6 kVA and has 50 turns on the secondary side. The number of turns on the primary side is ____________(a) 1000(b) 2000(c) 3000(d) 4000I had been asked this question in exam.Question is taken from Advanced Problems on Resonance in chapter Resonance & Magnetically Coupled Circuit of Network Theory

Answer»

The correct option is (a) 1000

Explanation: Turns ratio, N = \(\FRAC{N_2}{N_1}\)

Now, the turns ratio, n = \(\frac{V_2}{V_1}= \frac{120}{2400}\) = 0.05

Also, n = \(\frac{50}{N_1}\)

So, N1 = \(\frac{50}{0.05}\) = 1000 turns.



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