1.

An inductor of 3mH has a current i = 5(1 – e^-5000t). Find the corresponding maximum energy stored.(a) 37.5 mJ(b) 375 J(c) 37.5 kJ(d) 3.75 mJThis question was addressed to me in class test.The doubt is from Basic Network Concepts in section Circuit Elements and Kirchhoff’s Laws of Network Theory

Answer»

Correct choice is (a) 37.5 mJ

Best explanation: GIVEN L = 3 mH, i = 5(1 – E^-5000t)

V = L \(\FRAC{DI}{dt} = 3 × 10^{-3} \frac{d}{dt}[5(1-e^{-5000t})] = 75 e^{-5000t}\)

I = i(∞) = 5(1 – e^-∞) = 5 A

E = \(\frac{1}{2}\) LI^2 = 0.5 × 3 × 10^-3 × 5^2 = 37.5 mJ.


Discussion

No Comment Found

Related InterviewSolutions