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An isotope `._(Y)A^(X)` undergoes a series of m alpha and n beta disintegrations to form a stable isotope `._(Y -10)B^(X -32)`. The value of m and n are respectivelyA. 6 and 8B. 8 and 10C. 5 and 8D. 8 and 6 |
Answer» Correct Answer - D `._(Y)A^(X) rarr ._(Y - 10)B^(X - 32) + m ._(2)He^(4) + n ._(+1)e^(0)` Value of `m = (X -(X) -32)/(4) = 8` Value of `n = Y - Y - 10 - 2 xx 8 = 6` |
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