1.

An object 2.0 cm high is placed 20.0 cm in front of a concave mirror of focal length 10.0 cm. Find the distance from the mirror at which a screen should be placed in order to obtain a sharp image. What will be the size and nature of the image formed ?

Answer»

Solution :Here h = 2.0 cm, U = - 20.0 cm and f = - 10.0 cm.
`therefore""(1)/(v) = (1)/(f) - (1)/(u) = (1)/((-10)) - (1)/((-20)) = (-1)/(10) + (1)/(20) = - (1)/(20) rArr v = - 20` cm
Again `(h.)/(h) = - (v)/(u) rArr h. = - (v)/(u) h = - ((-20))/((-20)) xx 2.0 = - 2.0` cm
Hence, an image of LENGTH 2.0 cm is formed in front of mirror at a distance of 20 cm. The -ve sign of v and h. show that the image is REAL and inverted image.


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