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An object 2 cm high is placed at a distance of 16 cm from a concave mirror which produces a real image 3 cm high. Find the position of the image. |
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Answer» Solution :Height of object `h_1 =2` CM Height of real image `h_2 = -3` cm Magnification `m = (h_2)/(h_1) = (-3)/(2) = -1.5` We know that, `m = (-v)/(u )` Here, object distance `u= -16 cm` Substituting the value, we get `-1.5 = -(v)/((16)) rArr 1.5 = (v)/( 16) rArr = 16 XX (-1.5) = -24 c` The position of image is 24 cm in front of the mirror (negative sign indicates that the image is. on the LEFT side of the mirror). |
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