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An object 2cm tall is kept on the principal axis of a converging lens of focal length 8 cm. Find the position, nature and size of the image formed if the object is at 12cm from the lens. Also find the magnification produced by the lens. |
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Answer» Solution :Given: `h_0 = 2CM , f = 8cm ,u= -12cm , v ? ` ` 1/f = 1/v - 1/u` `1/v = 1/f + 1/u` `1/v = 1/8 - 1/12` `1/v = (3-2)/(24) = 1/24` REAL and INVERTED Real and inverted `(h_i)/(h_0) = v/u` ` (h_i)/((2) = (24)/(-12)` ` h_i= - 48/12 = -4` `h_o = - 4` MAGNIFICATION ` = v/u = (24)/(-12) = -2 ` |
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