An object 5.0 cm in length is placed at a distance of 20 cm in front of a convex mirror of radius of curvature 30 cm. Find the position of the image, its nature and size.

An object 5.0 cm in length is placed at a distance of 20 cm in front o

1.	An object 5.0 cm in length is placed at a distance of 20 cm in front of a convex mirror of radius of curvature 30 cm. Find the position of the image, its nature and size.
Answer» Solution :As radius of curvature of mirror R = 30 CM, hence f = R/2 = 30/2 = 15 cm. It is a convex mirror. Therefore, f = + 15 cm, U = -20 cm, h = 5.0 cm As `(1)/(v) + (1)/(u) = (1)/(f) rArr (1)/(v) + (1)/(-20) = (1)/(15) rArr (1)/(v) = (1)/(15) + (1)/(20) rArr (1)/(v) = (7)/(60)` `therefore ""v = + (60)/(7)` cm = + 8.6 cm The image is virtual and erect and is formed behind the mirror. `m = - (v)/(u) = - (60//7)/(-20) = (3)/(7)` `therefore` The size of image, h. = m.h = `(3)/(7) xx 5 cm = (15)/(7) cm = 2.2` cm