An object 5 cm in length is held 25 cm away from a converging lens of focal length 10 cm. Draw the ray diagram and find the position, size and the nature of the image formed.

An object 5 cm in length is held 25 cm away from a converging lens of

1.	An object 5 cm in length is held 25 cm away from a converging lens of focal length 10 cm. Draw the ray diagram and find the position, size and the nature of the image formed.
Answer» Solution :The ray diagram is drawn below Here f = + 10 cm, u = -25 cm and H = 5 cm. From lens formula `(1)/(V) - (1)/(u) = (1)/(f) rArr (1)/(v) - ((1)/(-25)) = (1)/(10) rArr (1)/(v) = (1)/(10) - (1)/(25) = (3)/(50)` `therefore v = 50//3` cm = 16.7 cm. The image is real and is formed at a distance of 16.7 cm from the lens on opposite side. As magnification `m = (h.)/(h) = (v)/(u)` `therefore""(h.)/(5 cm) = (+50 //3)/(-25) = - (2)/(3)` `rArr""h. = (-2)/(3) xx 5 = -(10)/(3)` cm Hence, the image is inverted and diminished in size.