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An object 5cm in length is held 25cm away froma converging lens of focal length 10cm. Draw the ray diagram and find the position, size and the nature of the image formed |
Answer» Solution : Height of the Object, `h_0=5cm` Distance of the object from converging lens, u-25cm Focal length of converging lens, f=10cm Using lens FORMULA `1/v-1/u=1/f` `1/v=1/f+1/u=1/(10)-1/(25)=(15)/(250)` `v=(250)/(15)=16.66cm` Also, for a converging lens, `(h_1)/(h_0)=v/u` `h_i=v/uxxh_0(50x5)/(3X(-25))=(10)/(-3)=-3.3cm` Thus, the image is inverted and formed at a distance of 16. 7 cm behind the lensand MEASURES 3.3 cm. The ray DIAGRAM is shown below. |
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