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An object is projected vertically upwards with a velocity (gr) ^1/2. What is the maximum height reached by the object if “R” is the radius of the earth and “g” is the acceleration due to gravity?(a) R/2(b) R(c) 2R(d) 4RThis question was posed to me by my college director while I was bunking the class.My question is from Gravitation in division Gravitation of Physics – Class 11 |
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Answer» RIGHT answer is (b) R Explanation: From the law of conservation of energy, we have; (m x v^2)/2 – (G x M x m)/R = -(G x M x m)/(R+H) m = MASS of object M = Mass of earth h = Maximum height of the object v = VELOCITY of projection (m x v^2)/2 – (g x m x R) = -(g x m x R^2)/(R+h) (g x R)/2 = (g x R x h)/(R+h) Therefore; h = R. |
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