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An object of mass 1 kg is raised through a height h. Its potential energy increased by 1 joule. Find the height h. |
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Answer» Solution :MASS : m - 1 kg, height = hm PE = mgh, TAKING g = `10 m/s^(2)` PE = (10h)J now potential energy increases by 1 JOULE `PE^(1) = (10h + 1)` Joule `PE^(1)` = mgh 1 = ( 10h + 1) `10h^(1)` = (10 h + 1) 10 `(h^(1) - h) = 1` `(h^(1) - h) = 1/10`. If body is on the GROUND h = 0 then `h^(1) = 0.1` m |
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