InterviewSolution
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InterviewSolution
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An object of mass 1 kg travelling in a straight line with a velocity of 10ms^(-1) collides with, and strikes to a stationary wooden block of mass 5 kg . Then they both move off together in the same straight line. Calculate the total momentum just before the impact andjust after the impact. Also calculate the velocity of the combined object . |
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Answer» Solution :Mass of the objcet `m_1 =1kg` Velcity of wooden block before collision `v_1=10m//s` Mass of the stationary wooden black `m_2=5 KG` Velocity of the wooden block before collision `V_2 =O m//s` Total MOMENTUM before collision = `m_1v_1+m_2v_2` `1(10)+5(0)=10 kg MS^(-1)` It is given that after collision the object and the wooden block stick together . Total mass of the combined system `=m_1+m_2` Velocity of the combined object =v. ACCORDING to the law of conservation momentum . Total momentum before collision = Total momentum after collision `m_1v_1+m_2v_2=(m_1+m_2)v` `1(10)+5(0)=(1+5)v` V=10/6 =5/3 The total momentum after collision is also 10 kg m/s Total momentum just before the impact =10 kg m/s Total momentum just after theimpact `=(m_1+m_2)v= 6+5//3= 10 kg ms^(-1)` |
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