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An object of mass 1kg is subjected to a variable force in x-direction. The force function is F = x^2 N. What is the work done in moving the object from x = 2 to 5?(a) 40(b) 39(c) 38(d) 69I have been asked this question in unit test.My question comes from Work Done by a Variable Force in section Work, Energy and Power of Physics – Class 11 |
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Answer» RIGHT answer is (b) 39 Easy EXPLANATION: The work is given by FORMULA W = \(\int_{x1}^{x2}\)F * dx. So, W = \(\int_{2}^{5}\)x^2 * dx = (5^3-2^3)/3 = 39 J. |
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