1.

An object of mass 2kg is thrown in the upward direction with velocity of 3ms^(-1). What would be the maximum potential energy of this object?

Answer»

`18J`
`4.5J`
`9J`
`2.25J`

Solution :At MAXIMUM height the POTENTIAL energy of the object is maximum. This potential energy would be the same as the initial KINETIC energy.
`E_(K)=(1)/(2)mv^(2)`
`=(1)/(2)xx(2kg)xx(3ms^(-1))^(2)=9J`


Discussion

No Comment Found

Related InterviewSolutions